Coprimality of consecutive Euler up/down numbers and the preperiod at odd prime powers
Abstract
Let Eₙ be the number of alternating permutations of {1,…,n}, so that sec z+tan z=Σ_(n ≥ 0)Eₙzⁿ/n!. Knuth and Buckholtz proved that (Eₙ mod q) is eventually periodic; write d(q) for its minimal eventual period and s(q) for its preperiod. Ramassamy conjectured s(pʳ)=r at every odd prime power; Güleç has recently disproved this with s(5⁵)=4, proved the companion period conjecture, and — on the strength of a search over pʳ ≤ 10¹⁰⁰⁰⁰⁰ — conjectured the weaker bound s(pʳ) ≥ r-2. We observe that his divisibility criterion turns that conjecture into a statement about greatest common divisors of consecutive Euler numbers: the single integer gcd(Eᵣ₋₃,Eᵣ₋₂,Eᵣ₋₁) settles the index r for every prime p at once, with no upper bound on p whatsoever. Computing the Euler numbers exactly to index 10 000 we prove that no prime divides three consecutive Euler up/down numbers of index at most 10 000, hence that s(pʳ) ≥ r-2 for every odd prime p and every 4 ≤ r ≤ 10001 — a region no search organised by the size of pʳ can cover. We classify, over all odd primes at once, the cells with s(pʳ) ≤ r-2 in that range: they are exactly p=43 and r ∈ {980,2786,4592,6398,8204}. In particular 43⁹⁸⁰ is the smallest odd prime power with s(pʳ) ≤ r-2, a minimality the source only suggests. We also determine the primes dividing two consecutive Euler up/down numbers below index 10 000 — exactly 43, 433, 1093, 5107, 13367 — and reproduce independently every computational assertion of the source's final section that names an explicit value, assertions its own declaration attributes to language models and for which no code is distributed. Every computation below is machine-checked in Lean 4; the passage from divisibility to preperiods is the source's criterion, quoted and not reproved.
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Claim ledger
Stated results
U1candidate2026-08-29
no prime divides three consecutive Euler up/down numbers up to index 10000; hence s(pʳ) >= r-2 for every odd prime p and every 4 <= r <= 10001
U2candidate2026-08-29
for every odd prime p and every 2 <= r <= 10001, s(pʳ) <= r-2 holds exactly at p = 43, r in 980, 2786, 4592, 6398, 8204; in particular 43⁹80 is the smallest odd prime power with s(pʳ) <= r-2
U3candidate2026-08-29
the primes dividing two consecutive Euler up/down numbers at index n < 10000 are exactly 43, 433, 1093, 5107, 13367
U4routine2026-08-29
negative controls for the gcd stream: consecutive Euler numbers are not always coprime (gcd(E 12, E 13) = 43), the deep hypothesis is realised (43² | E 978, 43 | E 979), and it is sharp (43³ does not divide E 977)
U5known data2026-08-29
s(5⁵) = 4: the lower bound s > 3 is unconditional (E 2503 = 2877 while E 3 = 2 mod 3125), the upper bound follows from the Knuth-Buckholtz threshold by one equality
U6known2026-08-29
d(pʳ) = pʳ⁻¹ lcm(p-1, 4) computed from the definition on 24 cells with r >= 2, and no proper divisor of 2500 is a period of (E n mod 5⁵) from index 5
U7known2026-08-29
the divisibility criterion of arXiv:2608.27058 Lemmas 6.1-6.2 agrees with the preperiod computed from the definition on all 24 tabulated cells
U8known data2026-08-29
444 exceptions to s(pʳ) = r with pʳ <= 10³00 and p <= 10⁶, none with s <= r-2, plus 17 explicit exceptions with p > 10⁶ – 461 in all, every one with s = r-1
U9known data2026-08-29
s(43⁹80) = 978: 43 | E 979, 43² | E 978, 43³ does not divide E 977
U10routine2026-08-29
negative controls for the cell computations: s(3⁷) = 7 = r, s(5⁴) = 4 = r, and 2500 is not a period of (E n mod 5⁶) from index 5
U11measurement2026-08-29
the exact gcd stream extended to index 20000 in C: still no prime dividing three consecutive Euler numbers, and the s <= r-2 cells for r <= 20001 are exactly 43⁹⁸⁰⁺¹⁸⁰⁶ᵏ, 0 <= k <= 10
This ledger entry is reported in prose and is not bound to a Lean theorem.Provenance
- Generated by
- Machina Mathematica
- Released by
- Korea Superintelligence Labs
- Source context
- Eₙ is the number of alternating permutations of 1, …, n (OEIS A000111):
- Snapshot
- 2026-09-07 03:53 UTC
- Ledger commit
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