One-and-a-half generation of simple Lie algebras over finite fields: the value k(sl₃(𝔽₂))=3
Abstract
For a simple Lie algebra L over a finite field, Kishnani and Singh define k(L) to be the least k such that every non-zero a ∈ L occurs as the first entry of some generating k-tuple, and observe that no clear answer for k(L) seems to be known; the number is the number of variables in their theorem on images of Lie polynomials. We determine one value: k(sl₃(𝔽₂)) = 3. The upper bound is a generating triple for each of the 255 non-zero elements. The lower bound is structural rather than a report that a search failed: ten proper Lie subalgebras of sl₃(𝔽₂), each containing the root element E₀₁, already cover the algebra, so every pair containing E₀₁ lies inside a proper subalgebra. We also determine the exceptional set exactly. Precisely 49 of the 255 non-zero elements lie in no generating pair, namely the 21 elements with A²=0 and the 28 with A²=A, equivalently the a with ad(a)³=ad(a)²; the remaining 206 each have an explicit partner. The mechanism is characteristic two: if A²=λ A then ad(A)²=λad(A), because the cross term 2AXA vanishes. In particular sl₃(𝔽₂) is 2-generated, as Cantor, Jezernik and Zozaya proved, and is nevertheless not one-and-a-half generated: the two properties come apart at the smallest algebra where they can be compared. All statements are machine-checked in Lean 4.
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Archived files
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Source snapshot 2026-08-30 15:34 UTC
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cbdd4158e43b6b8c63aef0ff15044705b1a7f500be46f5af4f8406a845aac08b
Claim ledger
Stated results
liegen-01routine2026-08-22
The object: sl₃(F₂) pinned to the trace-zero 3x3 matrices over ZMod 2
liegen-02candidate2026-08-23
k(sl₃(F₂)) <= 3: every non-zero element is the first entry of a generating triple
liegen-03candidate2026-08-23
k(sl₃(F₂)) > 2: E₀1 lies in no generating pair, certified by ten maximal proper subalgebras that cover the algebra
liegen-04candidate2026-08-23
k(sl₃(F₂)) = 3, both halves in one statement
liegen-05candidate2026-08-23
The exceptional set is exactly 49 elements, proved in both directions
liegen-06candidate2026-08-23
What the 49 are: A² = 0 or A² = A, equivalently ad(a)³ = ad(a)²
liegen-07known2026-08-22
Gate: sl₃(F₂) is 2-generated, as Cantor-Jezernik-Zozaya say it is
liegen-n1routine2026-08-22
Negative controls: too-small (k >= 2), vacuity of the generation test, vacuity of the subalgebra certificate
liegen-n2routine2026-08-22
Negative controls: the bracket is not associative, and one moved structure constant breaks Jacobi
liegen-08candidate2026-08-23
The neighbouring cells, probe only: k(sl₂(Fₚ)) = 2 for p = 3,5,7,11; k(sl₃(F₄)) >= 3
This ledger entry is reported in prose and is not bound to a Lean theorem.liegen-09candidate2026-08-30
Characteristic two obstruction: no A with rank(A - lambda*1) <= 1 lies in a generating pair of slₙ(F), for every n >= 3 and every field with 2 = 0
liegen-10candidate2026-08-30
New cells from the argument: k(sl₃(F_(2ʳ))) >= 3 for EVERY r, and k(sl₅(F₂)) >= 3
liegen-11candidate2026-08-30
Over an algebraically closed field of characteristic 2: k(sl₃(F-bar₂)) >= 3, so Bois's characteristic hypothesis cannot be relaxed for type A
liegen-12candidate2026-08-30
The exceptional set, structurally: exactly the A with rank(A - lambda*1) <= 1, which over F₂ is exactly the family's 49 and exactly A² = 0 or A² = A
liegen-n3routine2026-08-30
Negative controls for the characteristic-two argument: each of the four hypotheses refuted when dropped, plus the objects pinned
Provenance
- Generated by
- Machina Mathematica
- Released by
- Korea Superintelligence Labs
- Source context
- Subsection 2.3 of *Images of Lie Polynomials on simple Lie algebras*, arXiv:2605.19512 (Harish Kishnani, Anupam Singh), verbatim:
- Snapshot
- 2026-09-07 03:53 UTC
- Ledger commit
801848d7