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Combinatoricsmath.COIS-MM-kasami-apn
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The NSUCRYPTO 2019 conjecture on the Kasami APN function: exhaustive verification for n ≤ 18, an equidistribution of cubes at even n, and the weight distributions computed along the way

Abstract

Let gcd(k,n)=1, let F(x)=x^(4ᵏ-2ᵏ+1) be the Kasami function on 𝔽_(2ⁿ), and let Δ={F(b)+F(b+1)+1: b ∈ 𝔽_(2ⁿ)}. A conjecture posed as an unsolved problem at NSUCRYPTO 2019, originating with Carlet, asserts that #{(x,y,z) ∈ Δ³: v₁x+v₂y+(v₁+v₂)z=0}=2²ⁿ⁻³ for every pair of distinct nonzero v₁,v₂. The conjecture is open; the largest published verified range is n ≤ 13. We verify it exhaustively at n=14,15,16,17,18: for all 44 admissible pairs (n,k) in that range and for every one of the 2ⁿ-2 values of ρ=v₂/v₁ — at n=18, all 262,142 of them for each of the six admissible k — covering 7.3 · 10¹¹ ordered pairs (v₁,v₂) in total; together with the smaller cells this settles every admissible (n,k) with n ≤ 18 inside one machine-checked development. Part of the new range is confirmed a second time by counting the triples of Δ³ directly, with no character sum anywhere. Three further findings come out of the same computation. First, in every even cell computed here the triples split evenly over the three cosets of the cubes: writing s=v₁x+v₂y+(v₁+v₂)z, each coset receives exactly (2³ⁿ⁻³-2²ⁿ⁻³)/3 of the triples with s ≠ 0, so the cubic multiplicative character sum over them vanishes. This is verified exhaustively at n=4,6,8 and at sampled ρ for n=10,12; it is the datum Carlet identifies as what the even case needs, and it is pinned at its mean in the same way the conjecture itself is. Second, the associated character spectrum is the weight distribution of a binary code of Ding, and it confirms Ding's own conjecture on that code at every odd cell computed, m=15 and m=17 included; at m=18, outside the conjecture's scope, the code is a fifteen-weight [131072,18,64384] code. Third, writing max_(a ≠ 0)|2S(a)|=2^((n+v)/2) for the character sum S of Δ, the value v ∈ {1,3} holds at 46 of the 48 nondegenerate cells with n odd and 5 ≤ n ≤ 17 but fails at (15,4) and (15,11), where v=7; S is invariant under a ↦ a², and that locates the exceptional value at a=1 in both places where this data is anomalous. What makes those cells exceptional is open. Every theorem is machine-checked in Lean 4; the computations that are not are labelled as such.

Open review

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Archived files

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    Source snapshot 2026-08-30 15:34 UTC

    File fingerprintac2ae722eafa339a5df29892b3d180ca8f855cfe89e1ec21face3cb37dccb031

Claim ledger

Stated results

23 entries
KA1routine2026-08-28

The field model is checked, not assumed: F₂[x]/(redPoly n) is a field of order 2ⁿ for 3 <= n <= 20, the tabulated generator generates F_(2ⁿ)^*, the trace equals the parity-of-a-mask formula the fast evaluation of S uses, and the shift-and-xor product is commutative, associative and distributive on all 2³ⁿ triples for n <= 7

KA2known data2026-08-28

Table 2 of arXiv:2608.18584 in full: |supp S 0| and the value histogram of S on a!= 0 for all thirty-two (n,k) cells of its thirteen listed rows, together with the two sanity sums sum_(a!=0) S(a) = 2ⁿ⁻¹ and sum_(a!=0) S(a)² = 2²ⁿ⁻²

KA3routine2026-08-28

The two evaluations of S(a) = sum_(t in Delta) (-1)^(Tr(at)) agree for every a: the parity-table form Tr(at) = parity(phi(a) AND t) used by the sweeps, and the honest form that multiplies a by t in the field and takes the full trace of the product

KA4routine2026-08-28

The term-skipping sum the sweeps evaluate is the plain sum: zAcc = zAccPlain and hence zSweepOK n k = zSweepPlainOK n k, for every n and k, by induction

KA5routine2026-08-28

The conjecture verified at the level of its own definition, with no character sum anywhere: N(1,rho) = 2²ⁿ⁻³ counted directly over Delta³ for every rho in F_(2ⁿ) 0,1 and every admissible k, for every 3 <= n <= 12; plus sampled rho at n = 13

KA12known2026-08-28

The source's own top verified range redone here: the conjecture at n = 13 for all twelve admissible k, exhaustively over all 8190 rho, through the character reduction

KA6candidate2026-08-28

The conjecture at n = 14: N(v1,v2) = 2²ⁿ⁻³ for every admissible k (1,3,5,9,11,13) and every pair of distinct nonzero (v1,v2), exhaustively over all 2ⁿ - 2 values of rho = v2/v1

KA7candidate2026-08-28

The conjecture at n = 15: N(v1,v2) = 2²ⁿ⁻³ for every admissible k (1,2,4,7,8,11,13,14) and every pair of distinct nonzero (v1,v2), exhaustively over all rho

KA8candidate2026-08-28

The conjecture at n = 16: N(v1,v2) = 2²ⁿ⁻³ for every admissible k (1,3,5,7,9,11,13,15) and every pair of distinct nonzero (v1,v2), exhaustively over all rho

KA9candidate2026-08-28

The conjecture at n = 17: N(v1,v2) = 2²ⁿ⁻³ for all sixteen admissible k and every pair of distinct nonzero (v1,v2), exhaustively over all rho

KA10candidate2026-08-28

N(1,rho) = 2²ⁿ⁻³ counted from the definition, with no character sum, at sampled rho for n = 14, 15, 16 (every admissible k) and n = 17

KA13routine2026-08-28

The spectrum of S continued past the last row of the source's Table 2: |supp S 0| and the full value histogram of S on a!= 0 for n = 14, 15, 16 (every admissible k) and n = 17 (k = 1,2,3,5), with both of the source's sanity sums – equivalently, the complete weight distribution of the code C_(D(f)) of arXiv:1511.00321 for the Kasami defining set at those m (2026-08-28: also binds 16 SpectrumOdd fill-in theorems for odd n <= 13 cells missing from the source Table 2)

KA14routine2026-08-28

The source's Proposition 4.1 tested against the definition where it has content: 2ⁿ N(1,rho) = |Delta|³ + Z(rho) at ten (n,k) with gcd(k,n) > 1, where |Delta|!= 2ⁿ⁻¹ and Z(rho) is a large nonzero number varying with rho, and at seven admissible (n,k)

KA11routine2026-08-28

Negative controls: the constant 2²ⁿ⁻³ is refuted from both sides and off by one; gcd(k,n) = 1 is not idle (at every tested (n,k) with gcd > 1 both |Delta| = 2ⁿ⁻¹ and the conjecture fail, with explicit nonzero values of Z); 'distinct nonzero v1,v2' is not idle (at v1 = v2 and at v2 = 0 the count is 2²ⁿ⁻², twice the conjectured value); and the field check rejects reducible moduli

KA15candidate2026-08-28

The conjecture at n = 18: N(v1,v2) = 2²ⁿ⁻³ for every admissible k (1,5,7,11,13,17) and every pair of distinct nonzero (v1,v2), exhaustively over all 262142 values of rho = v2/v1

KA16routine2026-08-28

The spectrum of S at the whole n = 18 cell: |supp S 0| and the value histogram of S on a!= 0 for all six admissible k, with both of the source's sanity sums – equivalently the complete weight distribution of the code C_(D(f)) of arXiv:1511.00321 at m = 18, a fifteen-weight [131072, 18, 64384] binary code

KA17routine2026-08-28

A rho-sweep split into two consecutive ranges is the whole sweep: zLoop is additive in its fuel, zLoop T2 L M tgt (a+b) rho = zLoop... a rho && zLoop... b (rho+a), by induction; hence zSweepOK n k = zSweepChunk n k 2 c1 && zSweepChunk n k (2+c1) c2 whenever c1 + c2 = 2ⁿ - 2

KA18candidate2026-08-28

N(1,rho) = 2³³ counted from the definition over Delta³, with no character sum anywhere, at sampled rho for n = 18 (k = 5 and k = 7)

KA19routine2026-08-28

Negative controls for the n = 18 work: a chunk is exactly its range and no more (a chunk true, the whole sweep false, at an inadmissible cell); the split arithmetic is a real constraint; the split lemma reproduces an independently checked sweep at (10,3); and the constant 0 is pinned at (18,5) from both sides

KA20routine2026-08-28

The Dillon-Dobbertin invariant of Delta, checked from the definition: |Delta* ∩ mu Delta*| = 2ⁿ⁻² - 1 for every mu!= 1, at every admissible (n,k) with 5 <= n <= 15 and at (16,3), (16,7)

KA21routine2026-08-28

The twelve n = 17 spectrum cells that Spectrum17.lean left out (k = 4,6,7,8,9,10,11,12,13,14,15,16), completing all sixteen – hence every admissible (n,k) with n odd and 5 <= n <= 17

KA22routine2026-08-28

Delta is closed under squaring (at every admissible (n,k) with 5 <= n <= 16 and all six cells at n = 18) and S is Frobenius-invariant: S(a²) = S(a) for every a (at every admissible (n,k) with 5 <= n <= 16 and at (18,5)); hence every level set of S is a union of cyclotomic cosets, and a level set of size 1 must be 1. At (15,4) and (18,5) the unique extreme value of S is therefore S(1) = 1024 and S(1) = -2560

KA23candidate2026-08-28

The cube-refined triple counts that Carlet names as what the even-n case needs, and their three-coset refinement: for gcd(k,n) = 1, n even and every pair of distinct nonzero v1,v2, writing s = v1x+v2y+(v1+v2)z and C for the cubes, #(x,y,z) in Delta³: s in C = #s in wC = #s in w²C = (2³ⁿ⁻³ - 2²ⁿ⁻³)/3, hence #s a nonzero cube = (2³ⁿ⁻³ - 2²ⁿ⁻³)/3 and #s a non-cube = 2(2³ⁿ⁻³ - 2²ⁿ⁻³)/3 – equivalently the cubic multiplicative character sum over the triples with s!= 0 vanishes. Exhaustively over all rho at n = 4, 6, 8 (every admissible k, both cosets) and at (10,3), and at sampled rho for (10,7), (12,5), (12,7)

Provenance

Generated by
Machina Mathematica
Released by
Korea Superintelligence Labs
Source context
Let n ≥ 3 and k be positive integers with gcd(k,n) = 1, put
Snapshot
2026-09-07 03:53 UTC
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