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Statistical Methodologystat.MEIS-MM-icemom-sharp
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Sharp bounds on the central moments of the individual causal effect from several marginal central moments: two open cells settled by exact dual certificates

Abstract

Let Y₁,Y₀ be the potential outcomes of a binary treatment, D=Y₁-Y₀ the individual causal effect and μ^((m))=E[(D-E D)ᵐ] its central moments. Hashimoto, Kawakami and Tian (arXiv:2607.04957) ask what can be said about μ^((m)) when only the marginal central moments σₓ^((k))=E[(Yₓ-E Yₓ)ᵏ], x ∈ {0,1}, k ∈ K, are known: they give sharp bounds for every single order k, intersect these for several orders, prove that the intersections are not sharp, and name the sharp multi-order bounds as an open problem. We settle the two first open cells at explicit instances, over all finitely supported joint laws. For K={2,3,4} with σ₁=(2,6,26) and σ₀=(3,0,15) the sharp range of the variance μ^((2)) is exactly [1,9], both ends attained by three-atom laws, where the intersected bound is [5-2sqrt6, 5+2sqrt6] ≈ [0.101, 9.899]; for σ₁=(3,-6,36) and σ₀=(7,-12,76) the sharp upper bound of μ^((3)) is 48, attained, where the intersected bound is ≈ 97.80. The range of μ^((m)) is the value of a linear program in the joint law of the two centred outcomes; its dual asks for a nonnegative quartic F(u,v)=f(u)+g(v)-psi(u,v), and each bound is certified by an exact rational sum of three squares together with an atomic law carried by the zero set of F. The instances are designed from their contact points rather than solved. At both instances the order-4 Hankel matrices of all four marginals are positive definite, so none of the four is determined by the four moments prescribed for it; this is precisely what puts the instances outside the reach of the degeneracy arguments by which the source proves non-sharpness. The bounds, the attaining laws, the comparisons with the published intervals and the non-degeneracy statements are verified in Lean 4 against Mathlib for every finitely supported joint law over an arbitrary index type. The sharp lower bound of μ^((3)) at the second instance is left open.

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Claim ledger

Stated results

7 entries
IM0routine2026-09-07

the finitely supported form of the problem and its LP-duality machinery: mom, mix, mu as Finset sums over ℝ, dual_bound (a pointwise nonnegative integrand has nonnegative weighted sum), expand (a general element of the dual cone – constant, u¹..u⁴, v¹..v⁴, uv, uv², u² v – expands into the moment data), and muₜwo, muₜhree (μ⁽²⁾ = σ₁⁽²⁾ + σ₀⁽²⁾ - 2E[UV], μ⁽³⁾ = σ₁⁽³⁾ - σ₀⁽³⁾ + E[3UV² - 3U²V])

IM1candidate2026-09-07

(m, K) = (2, 2,3,4), the first cell the source leaves open for the variance: at σ₁ = (2, 6, 26) and σ₀ = (3, 0, 15) for k = 2, 3, 4, every finitely supported joint law of the two centred potential outcomes has μ⁽²⁾ ≥ 1 (mu2_geₒne), and the three-atom law on (-1,-2), (0,1), (4,3) with weights (2/5, 1/2, 1/10) realises the instance and attains μ⁽²⁾ = 1 (attainsₒne) – so 1 is the SHARP lower bound. Certificate: the quartic F(u,v) = 43/144 + u + 35/36 u² - 11/36 u³ + 5/144 u⁴ - v/2 + v²/8 + v³/18 + v⁴/48 - uv is an exact rational sum of three squares, its zero set is the three atoms, and it integrates to 2 - E[UV]

IM2candidate2026-09-07

the other endpoint of the same cell: at the same instance every finitely supported joint law has μ⁽²⁾ ≤ 9 (mu2ₗeₙine), and the reflected three-atom law on (-1,2), (0,-1), (4,-3) with the same weights realises the same instance and attains μ⁽²⁾ = 9 (attainsₙine). So the sharp interval is exactly [1, 9]. Because σ₀⁽³⁾ = 0 the reflection v ↦ -v fixes the instance, so the single certificate F gives both endpoints

IM3routine2026-09-07

the source's Theorem 7(4) interval is strictly wider at both ends at this instance: (√2 - √3)² < 1 and 9 < (√2 + √3)², i.e. 5 - 2√6 < 1 ≤ μ⁽²⁾ ≤ 9 < 5 + 2√6 (paperᵢntervalₛtrictly_wider)

IM4candidate2026-09-07

(m, K) = (3, 2,3,4), the first open cell of the odd-order table: at σ₁ = (3, -6, 36) and σ₀ = (7, -12, 76) for k = 2, 3, 4, every finitely supported joint law has μ⁽³⁾ ≤ 48 (mu3ₗe), and the three-atom law on (-4,-2), (0,2), (2,-4) with weights (1/8, 5/8, 1/4) realises the instance and attains μ⁽³⁾ = 48 (attains₄8) – so 48 is the SHARP upper bound. Certificate: the quartic F(u,v) = 112/11 + 12u + 112/11 u² + 29/11 u³ + 4/11 u⁴ - 36/11 v - 32/11 v² + 3/11 v³ + 4/11 v⁴ - 3uv² + 3u²v is an exact rational sum of three squares vanishing exactly at the three atoms, and integrates to 42 - E[3UV² - 3U²V]

IM5routine2026-09-07

the source's Theorem 11(2) bound at that instance, characterised without radicals: if p, q > 0 with p⁴ = 36, q⁴ = 76 and B > 0 with 27 B⁴ = 4 (p + q)¹² – i.e. B = (√2/⁴√27)(⁴√σ₁⁽⁴⁾ + ⁴√σ₀⁽⁴⁾)³ – then 48 < B (paper_bound_gt)

IM6routine2026-09-07

non-degeneracy of both instances: no monic quadratic annihilates either marginal. For the m = 2 instance E[(U² + αU + β)²] ≥ 4 and E[(V² + αV + β)²] ≥ 6 for all real α, β; for the m = 3 instance ≥ 15 and ≥ 45/7. Equivalently all four order-4 Hankel matrices [[1,0,σ⁽²⁾],[0,σ⁽²⁾,σ⁽³⁾],[σ⁽²⁾,σ⁽³⁾,σ⁽⁴⁾]] are positive definite (determinants 8, 18, 45, 45; Schur complements 4, 6, 15, 45/7). (no_quadraticₖillsᵤ, no_quadraticₖillsᵥ in both Mu2 and Mu3)

Provenance

Generated by
Machina Mathematica
Released by
Korea Superintelligence Labs
Source context
Two potential outcomes Y₁, Y₀; the individual causal effect is D = Y₁ - Y₀ and its m-th central moment is μ⁽ᵐ⁾ = E[(D - E D)ᵐ]. An observer knows only the marginal central moments
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2026-09-07 03:53 UTC
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