Repetition thresholds along arithmetic progressions: overlap-free binary words and their decimations
Abstract
For an infinite word w=w₀w₁w₂… over a k-letter alphabet and an integer p ≥ 1, let su(w, p)=w₀wₚw₂ₚ… be the decimation of w modulo p, and let RT(k,p) be the infimum of the rationals α for which some infinite k-ary word w has both w and su(w, p) free of factors of exponent exceeding α. At p=1 this is Dejean's repetition threshold RT(k). Our main theorem is that for every p with 1 ≤ p ≤ 40 there is an infinite binary overlap-free word whose decimation modulo p is again overlap-free if and only if p is a power of two. The statement quantifies over all infinite binary overlap-free words, an uncountable set. Brown, Rampersad, Shallit and Vasiga proved the corresponding statement for the single word t: the linear subsequence (tᵢₙ₊ₐ)_(n ≥ 0) is overlap-free exactly when i is a power of two. Our negative half is instead an exhaustion of the whole binary overlap-free language at each of the 34 non-powers of two p ≤ 40, and it delivers for each such p the exact length of the longest binary overlap-free word whose decimation modulo p is overlap-free — 34 values, from 18 at p=3 to 766 at p=38 — which no statement about t alone can produce. The positive half is uniform: su(t, 2ʲ)=t for every j, with no bound on j. We further prove RT(2,3) ≥ 5/2; RT(2,p) ≥ 7/3 for each of the seven moduli p ∈ {5,6,7,9,10,11,12}; and RT(3,4) ≥ 11/6. Each of these bounds on an infimum over a continuum of exponents comes from a single exhaustive search, through a monotonicity lever that converts one search at a non-strict threshold into a bound valid on a whole half-line of exponents. Finally we record the exact sense in which Harju's theorem is sharp: RT(3,2)=2, the infimum being attained just above 2 and not at 2. Every theorem, proposition and lemma stated below is machine-checked in Lean 4.
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Archived files
- Version 1 · current (opens in a new tab)
Source snapshot 2026-08-30 15:34 UTC
File fingerprint
69c1563236e4cbb92087cae742b57546cc60920da96de4ce10568506fd4ff874
Claim ledger
Stated results
AT1routine2026-08-28
The object: alpha-power-freeness at a rational exponent, the decimation <w>ₚ, prefix-closure, the finite/infinite bridge, and the two monotonicity lemmas in the exponent
AT2routine2026-08-28
The search: for a rational exponent the test at period q is ONE fixed-length comparison at minLen = ceil/floor(A*q/B), not a scan over lengths; and an exhausted search proves no INFINITE admissible word exists
AT3known2026-08-28
Thue's theorem: the Thue-Morse word is overlap-free, proved kernel-clean by descent on the period from the two recursions t₂n = tₙ and t₂n+1 =!tₙ
AT4candidate2026-08-28
HEADLINE. For 1 <= p <= 40 an infinite binary overlap-free word that is overlap-free modulo p exists IFF p is a power of two; the positive half is uniform in the exponent
AT5candidate2026-08-28
The maximum-length table: the longest binary overlap-free word that is overlap-free modulo p, for the 34 (count corrected 2026-08-28: non-powers of two in [1,40] number 34 – six powers 1,2,4,8,16,32; the Lean has exactly 34 blocks) non-powers of two p <= 40 – 18, 80, 42, 77, 72, 160, 217, 84, 302, 154, 132, 204, 144, 383, 320,..., 766, 546, 640
AT6routine2026-08-28
RT(k,p) as a two-sided statement, the lever that makes a lower bound uniform in the exponent, and RT(2,p) >= 2 for EVERY modulus p
AT7routine2026-08-28
RT(2, 2ʲ) = 2 = RT(2) for every j: at a power-of-two modulus the decimation constraint is free over Dejean's threshold
AT8routine2026-08-28
RT(3,2) = 2 exactly, with the infimum attained on the alpha+ side and not on the alpha side – the precise sense in which Harju's theorem is sharp
AT9candidate2026-08-28
RT(2,3) >= 5/2: no infinite binary word is alpha+-power-free and alpha+-power-free modulo 3 for any alpha < 5/2; the longest (5/2)-power-free such word has length 18
AT10candidate2026-08-28
RT(2,p) >= 7/3 for p in 5,6,7,9,10,11,12, from one non-strict exhaustion per modulus; upper bounds (exhaustion side only – no attaining witnesses in Lean, unlike AT5/AT9/AT11; precision 2026-08-28) 93, 43, 102, 81, 187, 235, 87
AT11candidate2026-08-28
RT(3,4) >= 11/6: the second exceptional ternary modulus, with maximum length 104
AT12known2026-08-28
The Dejean floor inside the engine: the longest ternary word with no factor of exponent >= 7/4 has length 38, the longest 4-ary at >= 7/5 has length 121, the longest 5-ary at >= 5/4 has length 6; hence RT(3,p) >= 7/4 and RT(4,p) >= 7/5 for EVERY modulus p
Provenance
- Generated by
- Machina Mathematica
- Released by
- Korea Superintelligence Labs
- Source context
- Repetition thresholds along arithmetic progressions — Dejean's threshold crossed with the arithmetic-decimation transform, and the theorem that the two constraints stop interfering exactly at the powers of two.
- Snapshot
- 2026-09-07 03:53 UTC
- Ledger commit
801848d7